The equilibrium constant for the reaction N_{ | vedclass

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(B) The equilibrium constant $(K_c)$ depends only on temperature for a given reaction.$A$ catalyst provides an alternative pathway with lower activati

Vedclass · Accepted Answer

$4 	imes 10^{-4}$

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(B) The equilibrium constant $(K_c)$ depends only on temperature for a given reaction.$A$ catalyst provides an alternative pathway with lower activation energy,which increases the rate of both the forward and backward reactions to the same extent.Since the catalyst does not change the thermodynamic stability of reactants or products,it does not alter the value of the equilibrium constant.Therefore,the equilibrium constant remains $4 	imes 10^{-4}$ at $2000 \ K$.

The equilibrium constant for the reaction $N_{2(g)} + O_{2(g)} \rightleftharpoons 2NO_{(g)}$ is $4 \times 10^{-4}$ at $2000 \ K$. In the presence of a catalyst,equilibrium is attained ten times faster. Therefore,the equilibrium constant in the presence of the catalyst at $2000 \ K$ is:

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